Area of Triangles
Let's learn about the area of Triangle. Let's start with the basics.
1. Right triangle and Triangle with a height.

Area of both triangles equals: A = h * c / 2
Let's prove for the second triangle (the first one can be proved similarly):

Area(ADC) = h*(d+c)/2, which is half area of rectangle with sides d+c and h
Area(ADB) = h*d/2, which is half area of rectangle with sides d and h
Area(ABC) = Area(ADC) - Area(ADB) = h*(d+c)/2 - h*d/2 = h*c/2
Thus, Area(ABC) = h*c/2
2. Triangle with two sides and angle
A = b*c*sin(A)/2
Let's prove it:
Draw a height,

A = b * c * sin(A)/2
sin(A) = opposite/hypotenuse = h / b
thus,
A = b * c * (h/b) /2
which can be simplified to:
A = c * h / 2 and this formula we've proved above.
The End.
