---
title: "Area of Triangles"
description: "Let's learn about the area of Triangle. Let's start with the basics. 1. Right triangle and Triangle ..."
author: "Madiyar92"
published: "2016-01-17T12:25:16+00:00"
modified: "2016-01-18T03:22:50+00:00"
locale: "ru"
canonical_url: "https://yvision.kz/post/area-of-triangles-673526"
markdown_url: "https://yvision.kz/post/area-of-triangles-673526/markdown"
site_name: "Yvision.kz"
---

# Area of Triangles

> Let's learn about the area of Triangle. Let's start with the basics. 1. Right triangle and Triangle ...

Let's learn about the area of Triangle. Let's start with the basics.

**1. Right triangle and Triangle with a height.**

![Area of Triangles](http://storage.yvision.kz/images/user/madiyar92/QMFKPKvxAb44pF7Ejh8v8Z01973xar.png)

Area of both triangles equals: A = h * c / 2

Let's prove for the second triangle (the first one can be proved similarly):

![Area of Triangles](http://storage.yvision.kz/images/user/madiyar92/Y7z57my5rtaMQYLJtYzmvqukH75IYh.png)

Area(ADC) = h*(d+c)/2, which is half area of rectangle with sides **d+c** and **h**

Area(ADB) = h*d/2, which is half area of rectangle with sides **d** and **h**

Area(ABC) = Area(ADC) - Area(ADB) = h*(d+c)/2 - h*d/2 = h*c/2

**Thus, Area(ABC) = h*c/2**

**2. Triangle with two sides and angle**

###

![Area of Triangles](http://storage.yvision.kz/images/user/madiyar92/cGi6lI8yQWVxDT6yhrYoYCAi9fK8Nz.png)

A = b*c*sin(A)/2

**Let's prove it**:

Draw a height,

![Area of Triangles](http://storage.yvision.kz/images/user/madiyar92/TPSPXhQkwhN8JWnBpSTupfv95t17A4.png)

A = b * c * sin(A)/2

sin(A) = opposite/hypotenuse = h / b

**thus,**

A = b * c * (h/b) /2

which can be simplified to:

**A = c * h / 2** and this formula we've proved above.

**The End.**

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Source: [https://yvision.kz/post/area-of-triangles-673526](https://yvision.kz/post/area-of-triangles-673526)